How will you determine the %age purity of KD Cr:O when you are provided with the 0.1 M Mohr's salt solution is provided

 To determine the percentage purity of potassium dichromate (K₂Cr₂O₇) using a 0.1 M solution of Mohr's salt (ferrous ammonium sulfate, Fe(NH₄)₂(SO₄)₂·6H₂O), you can perform a redox titration. Here is a step-by-step outline of the procedure:

Materials Needed

  • Potassium dichromate sample
  • 0.1 M Mohr's salt solution
  • Dilute sulfuric acid (H₂SO₄)
  • Burette
  • Pipette
  • Conical flask
  • Indicator (typically diphenylamine sulfonate or N-phenylanthranilic acid)

Procedure

  1. Prepare the Sample Solution: Accurately weigh a sample of the potassium dichromate and dissolve it in distilled water to prepare a solution of known concentration.

  2. Set Up the Titration:

    • Fill the burette with the 0.1 M Mohr's salt solution.
    • Pipette a known volume of the potassium dichromate solution into a conical flask.
    • Add an appropriate amount of dilute sulfuric acid to the flask to maintain an acidic medium (usually 1-2 mL of 1 M H₂SO₄).
  3. Add the Indicator:

    • Add a few drops of the chosen redox indicator to the flask. Diphenylamine sulfonate is commonly used, which changes color at the endpoint of the titration.
  4. Titrate:

    • Titrate the potassium dichromate solution with the 0.1 M Mohr's salt solution, swirling the flask continuously, until you reach the endpoint indicated by a distinct color change.
  5. Calculate the Amount of Mohr's Salt Used:

    • Record the volume of Mohr's salt solution used to reach the endpoint.

Calculation

  1. Determine the Moles of Mohr's Salt Used:

    Moles of Mohr’s salt=Volume (L) of Mohr’s salt×0.1M\text{Moles of Mohr's salt} = \text{Volume (L) of Mohr's salt} \times 0.1 \, \text{M}
  2. Calculate the Moles of Potassium Dichromate: The balanced redox reaction between potassium dichromate and Mohr's salt in acidic medium is:

    Cr2O72+14H++6Fe2+2Cr3++7H2O+6Fe3+\text{Cr}_2\text{O}_7^{2-} + 14\text{H}^+ + 6\text{Fe}^{2+} \rightarrow 2\text{Cr}^{3+} + 7\text{H}_2\text{O} + 6\text{Fe}^{3+}

    According to the stoichiometry of the reaction, 1 mole of Cr2O72\text{Cr}_2\text{O}_7^{2-} reacts with 6 moles of Fe2+\text{Fe}^{2+}. Therefore:

    Moles of Cr2O72=Moles of Mohr’s salt6\text{Moles of } \text{Cr}_2\text{O}_7^{2-} = \frac{\text{Moles of Mohr's salt}}{6}
  3. Determine the Mass of Potassium Dichromate: Using the molar mass of potassium dichromate (294.18 g/mol):

    Mass of Cr2O72=Moles of Cr2O72×294.18g/mol\text{Mass of } \text{Cr}_2\text{O}_7^{2-} = \text{Moles of } \text{Cr}_2\text{O}_7^{2-} \times 294.18 \, \text{g/mol}
  4. Calculate the Percentage Purity: Compare the mass of potassium dichromate obtained from the titration to the initial mass of the sample:

    Percentage purity=(Mass of pure Cr2O72Mass of sample)×100\text{Percentage purity} = \left( \frac{\text{Mass of pure } \text{Cr}_2\text{O}_7^{2-}}{\text{Mass of sample}} \right) \times 100

Example Calculation

Let's say you weighed a 0.5 g sample of potassium dichromate and used 20 mL of 0.1 M Mohr's salt solution in the titration.

  1. Moles of Mohr's salt:

    Moles of Mohr’s salt=0.02L×0.1M=0.002moles\text{Moles of Mohr's salt} = 0.02 \, \text{L} \times 0.1 \, \text{M} = 0.002 \, \text{moles}
  2. Moles of potassium dichromate:

    Moles of Cr2O72=0.0026=0.000333moles\text{Moles of } \text{Cr}_2\text{O}_7^{2-} = \frac{0.002}{6} = 0.000333 \, \text{moles}
  3. Mass of potassium dichromate:

    Mass of Cr2O72=0.000333×294.18g/mol=0.098g\text{Mass of } \text{Cr}_2\text{O}_7^{2-} = 0.000333 \times 294.18 \, \text{g/mol} = 0.098 \, \text{g}
  4. Percentage purity:

    Percentage purity=(0.0980.5)×100=19.6%\text{Percentage purity} = \left( \frac{0.098}{0.5} \right) \times 100 = 19.6\%

Thus, the potassium dichromate sample is 19.6% pure.

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